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Hibridization of carbon and oxygen atoms in molecule *(e): C1: SP2 C2: SP2 O: SP3 C3: SP2 C4: SP3 O2 (the double bond O): SP2 By: hendrik -_5. The Central Carbons is carbon with the most subtituents, so the hibridization is SP3 and the bond is 109,28 because it is tetrahedral b. There are 5 double bond in molecule (f), the phi electron exist in the top and bottom of the double bonds, so, the electron phi total is 5x2=10 electron phi 4. Look at the double bond carbon C1 and C2, that is SP2 Hybridization, because there are 3 Hydrogen atom, it must lie in the same plane to be stable, so the atom is C, C, H, H, H, O 3. So the name is 7(cyclohexa-1,3-dienyl)-hepta-3,5-dien-2-one 2. The carbon chain is 7, and we are naming from the nearest end of function group (C2), so the double bounds are in C3 and C5. The cyclohexene subtituent name is cyclohexa-1,3-dienyl. The function group is ketone, we must naming the complex subtituent first. So the name is 1-ethenyl ethanoate or 1-vinyl ethanoate or 1-vinyl acetate f. The function group of the molecule is ester, (alkyl alcanoate) alkyl is a naming for subtituent beside O. Wbchse philosophy syllabus for xi and xii as test nga lenda.
#BUKU BIOLOGI KELAS XI ERLANGGA PDF FILES DOWNLOAD#
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#BUKU BIOLOGI KELAS XI ERLANGGA PDF FILES INSTALL#
Rmskin Install Download.īiologi xii ipa erlangga pdf file was indexed by our crawlers and is ready for downloading. Because the priority isn’t at the same side, hte isomer is Entgegen (E) so the name of the molecule is (E) 3-methyl-2-heptene e.
The subtituent in C3 is C4H9 (top) and CH3 (bottom), C4H9 is a priority subtituent because the second bond is C whereas CH3 second bond is H, so the priority in C3 is bottom. There is a double bond in C2 and C3, the subtituent in C2 is H (top) and C in CH3 (bottom), the priority of subtituents are I, Cl, Br, F, O, N, C, H, so, the priority in C2 is top. 7 carbon chain, ketone function group in C3 so the IUPAC Name is 3-heptanone d.